Y^2+4x^2=16

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Solution for Y^2+4x^2=16 equation: 



^2+4Y^2=16

We move all terms to the left:

^2+4Y^2-(16)=0

determiningTheFunctionDomain
4Y^2-16+^2=0

We add all the numbers together, and all the variables

4Y^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{0}{8}=0$

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